add two numbers II
public class Solution {
/**
* @param l1: the first list
* @param l2: the second list
* @return: the sum list of l1 and l2
*/
public ListNode addLists2(ListNode l1, ListNode l2) {
l1 = reverse(l1);
l2 = reverse(l2);
return reverse(addList1(l1, l2));
}
private ListNode reverse(ListNode head) {
ListNode prev = null;
while (head != null) {
ListNode temp = head.next;
head.next = prev;
prev = head;
head = temp;
}
return prev;
}
private ListNode addList1(ListNode l1, ListNode l2) {
ListNode dummy = new ListNode(0);
ListNode tail = dummy;
int carry = 0;
while (l1 != null && l2 != null) {
tail.next = new ListNode((l1.val + l2.val + carry) % 10);
tail = tail.next;
carry = (l1.val + l2.val + carry) / 10;
l1 = l1.next;
l2 = l2.next;
}
while (l1 != null) {
tail.next = new ListNode((l1.val + carry) % 10);
tail = tail.next;
carry = (l1.val + carry) / 10;
l1 = l1.next;
}
while (l2 != null) {
tail.next = new ListNode((l2.val + carry) % 10);
tail = tail.next;
carry = (l2.val + carry) / 10;
l2 = l2.next;
}
while (carry != 0) {
tail.next = new ListNode(carry % 10);
tail = tail.next;
carry = carry / 10;
}
return dummy.next;
}
}
class Solution:
def addTwoNumbers(self, l1: ListNode, l2: ListNode) -> ListNode:
num1,num2 = 0,0
while l1 or l2:
if l1:
num1 = num1*10 + l1.val
l1 = l1.next
if l2:
num2 = num2*10 + l2.val
l2 = l2.next
dummhead = ListNode(0)
for num in str(num1+num2):
newnode = ListNode(int(num))
if not dummhead.next:
dummhead.next = tail = newnode
else:
tail.next = newnode
tail = tail.next
return dummhead.next
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