Permutations II
public class Solution {
/*
* @param nums: A list of integers.
* @return: A list of permutations.
*/
public List<List<Integer>> permuteUnique(int[] nums) {
List<List<Integer>> result = new ArrayList<>();
List<Integer> path = new ArrayList<>();
boolean[] visited = new boolean[nums.length];
dfs(nums, result, path, visited);
return result;
}
private void dfs(int[] nums, List<List<Integer>> result, List<Integer> path, boolean[] visited) {
if (path.size() == nums.length) {
result.add(new ArrayList<>(path));
}
for (int i = 0; i < nums.length; i++) {
if (visited[i]) continue;
//数字有可能不在一起
boolean skip = false;
for (int j = 0; j < i; j++) {
if (nums[j] == nums[i] && !visited[j]) {
skip = true;
break;
}
}
if (skip) continue;
visited[i] = true;
path.add(nums[i]);
dfs(nums, result, path, visited);
path.remove(path.size() - 1);
visited[i] = false;
}
}
}
// 排序去重
public class Solution {
/*
* @param nums: A list of integers.
* @return: A list of permutations.
*/
public List<List<Integer>> permuteUnique(int[] nums) {
List<List<Integer>> result = new ArrayList<>();
List<Integer> path = new ArrayList<>();
Arrays.sort(nums);
boolean[] visited = new boolean[nums.length];
dfs(nums, result, path, visited);
return result;
}
private void dfs(int[] nums, List<List<Integer>> result, List<Integer> path, boolean[] visited) {
if (path.size() == nums.length) {
result.add(new ArrayList<>(path));
}
for (int i = 0; i < nums.length; i++) {
if (visited[i]) continue;
/*
boolean skip = false;
for (int j = 0; j < i; j++) {
if (nums[j] == nums[i] && !visited[j]) {
skip = true;
break;
}
}
if (skip) {
continue;
}
*/
//因为数组已经排序
if (i > 0 && nums[i - 1] == nums[i] && !visited[i - 1]) {
continue;
}
visited[i] = true;
path.add(nums[i]);
dfs(nums, result, path, visited);
path.remove(path.size() - 1);
visited[i] = false;
}
}
}
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